Decibels
Attenuation = Log10
Pin
Pout
Example 1: Pin = 10 mW, Pout=5 mWAttenuation = 10 log 10 (10/5) = 10 log 10 2 = 3 dB
Example 2: S/N = 30 dB => 10 Log 10 S/N = 30, or,
Log 10 S/N = 3.
S/N = 103
Bel
Pin
Pout
deciBel
Attenuation = 10 Log10
Since P=V2/R
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